288m^2-200=0

Solution for 288m^2-200=0 equation:

288m^2-200=0

a = 288; b = 0; c = -200;
Δ = b2-4ac
Δ = 02-4·288·(-200)
Δ = 230400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{230400}=480$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-480}{2*288}=\frac{-480}{576}
=-5/6
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+480}{2*288}=\frac{480}{576}
=5/6
$